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Class 12 | Physics
Q.14 NCERT Ch.4 - Moving Charges & Magnetism

A circular coil of 20 turns and radius 10 cm carries a current of 5A. Find the magnitude of the magnetic field at the centre of the coil.

AI Step-by-Step Solution

Step 1: Use B = mu_0 * N * I / (2R)

Step 2: B = (4pi x 10^-7) x 20 x 5 / (2 x 0.1)

Step 3: B = 6.28 x 10^-4 T

Answer: B = 6.28 x 10^-4 T = 0.628 mT

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Solve this integration problem

AI Tutor

I can see the question: Find the integral of x^2 * sin(x) dx

Step-by-Step Solution

1. Apply integration by parts: u = x^2, dv = sin(x)dx

2. du = 2x dx, v = -cos(x)

3. Apply IBP again for remaining integral

Answer: -x^2 cos(x) + 2x sin(x) + 2cos(x) + C

Can you explain step 3 more?

Type or snap a photo...
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