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A circular coil of 20 turns and radius 10 cm carries a current of 5A. Find the magnitude of the magnetic field at the centre of the coil.
Step 1: Use B = mu_0 * N * I / (2R)
Step 2: B = (4pi x 10^-7) x 20 x 5 / (2 x 0.1)
Step 3: B = 6.28 x 10^-4 T
Answer: B = 6.28 x 10^-4 T = 0.628 mT
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Solve this integration problem
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I can see the question: Find the integral of x^2 * sin(x) dx
Step-by-Step Solution
1. Apply integration by parts: u = x^2, dv = sin(x)dx
2. du = 2x dx, v = -cos(x)
3. Apply IBP again for remaining integral
Answer: -x^2 cos(x) + 2x sin(x) + 2cos(x) + C
Can you explain step 3 more?
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